Question

Calcule o valor de b de modo que cada sequencia seja uma pg
(b+3,b+17,b+59)

Answer 1

(b+3,b+17,b+59)

  (b+17) = (b+59)
  (b+3)      (b+17)

 (b+17)(b+17)=(b+3)(b+59)

b^2 + 34b + 289 = b^2 + 59b + 3b + 177

 62b - 34b = 289 - 177

       28b = 112

          b = 4

(b+3, b+17, b+69)

( 4+3, 4+17, b+69 )

(7, 21, 63)