Question

x² + y² = 20
x + y = 16

Answer 1

x=16-y

(16-y)²+y²=20

256-32y+y²+y²=20

2y²-32y+256-20=0

2y²-32y+236=0

2y²/2 -32y/2 +236/2=0/2

y²-16y+118=0

x=-(-16)+-\/(-16)²-4(1)(118)

x=16+-\/256-472

x=16+-\/-216/2

\/-216 Não existe raiz real.

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