Question

x2-5x+6=0 como resolvo?

Answer 1

$x^{2} -5x+6=0= \Delta= b^{2} -4.a.c= \Delta= -5^{2} -4.1.6= \Delta=25-24=1  x^{1} =-(-5)-+ \sqrt{1} /2=5-1/2=4/2=2 x^{2} =-(-5)-+ \sqrt{1} /2=5+1/2=6/2=3$



S{2,3}