Question

(3y-5)(y-5)+y²=0 como resolvo??????

Answer 1

a resposta y = 5/2 ................

Answer 2

(3y-5)(y-5)+y²=0
3y²-15y-5y+25+y²=0
4y²-20y+25=0

Delta=b²-4ac
Delta=(-20)²-4.4.25
Delta=400-400
Delta=0

x=-b+/-VDelta / 2.a
x= -(-20) +/- V0 / 2.4
x=20/8
x'=20/8 = 5/2
x"=5/2