Question

x2-8x+12=0 quero a resposta?

Answer 1

$x^{2} -8x+12=0= \Delta= b^{2} -4.a.c= \Delta= -8^{2} -4.1.12= \Delta=64-48=16  x^{1} =-(-8)-+ \sqrt{16}/2=8-4/2=4/2=2  x^{2} =-(-8)-+ \sqrt{16} /2=8+4/2=12/2=6$


S{2,6}