Question

(x+3)² + (x-3)² -116 =0​

Answer 1

(x+3)²+(x-3)²-116=0

x²+6x+3+x²+6x-3-116=0

x²+x²+6x+6x+3-3-116=0

2x²+12x-116=0

equação do segundo grau

a= 2 b=12 c =-116

∆=b²-4ac

∆= 12²-4.2.(-116)

∆=144-928

∆=-784

x=-b±√∆/2a

x'=-12+√-784/4

x"=-12-√-784/4