Question

***URGENTE***
Sabendo que $sen x = \frac{-3}{5} , com \frac{3x}{2} \ \textless \ x \ \textless \ 2x$ calcule cotg x

Answer 1

Resposta:

a) utilizando a relação fundamental

sen²x + cos²x = 1

(3/5)² + cos²x = 1

cos x = 4/5

b) tgx = senx/cosx = \frac{ \frac{3}{5} }{ \frac{4}{5} }

5

4

5

3

tgx = 3/4

c) cotg = 1/tgx

cotg = \frac{1}{ \frac{3}{4} }

4

3

1

cotg x = 4/3

d) secx = 1/cosx

secx = \frac{1}{ \frac{4}{5} }

5

4

1

secx = 5/4

e) cossecx = 1/senx

cossecx = \frac{1}{ \frac{3}{5} }

5

3

1

cossecx = 5/3