Question

Sendo A(3,2) e o coeficiente angular m= √3 construa a equação geral da reta
                                                                   5

Answer 1

$y-y_o=m(x-x_o)\\ \\ y-2= \sqrt{3}(x-3)\\ \\ y-2=\sqrt3x -3\sqrt3\\ \\ \boxed{\sqrt3x-y+2-3\sqrt3=0}$

Answer 2

$ax+by+c=0$

$m=\sqrt{3}$

$\sqrt{3}x+by+c=0$

$A(3,2)$

$y-y_0=m(x-x_0)$

$y-2=\sqrt{3}\cdot(x-3)$

$\sqrt{3}x-3\sqrt{3}=y-2$

$\sqrt{3}x-3\sqrt{3}-y+2=0$

$\sqrt{3}x-y+(2-3\sqrt{3})=0$