Question

seja a f(x)=x2-5x+4 uma funcao quadrativa, indique qual a alternativa correspondente as raizes ou zeros dessa funcao.

Answer 1

Resposta:

4 e 1

Explicação passo a passo:

Utilizando a fórmula de Bhaskara:

$f(x)=x^{2}-5x+4\\\\ a=1;\ b=-5;\ c=4\\\\\\\Delta=b^{2}-4\cdot a\cdot c\\\\ \Delta=(-5)^{2}-4\cdot 1\cdot 4\\\\ \Delta=25-16\\\\\Delta=9\\\\\\x=\frac{-b\pm\sqrt{\Delta} }{2a}\\\\ x=\frac{-(-5)\pm\sqrt{9} }{2}\\\\ x=\frac{5\pm3}{2} \\\\\\x1=\frac{5+3}{2} \\\\x1=\frac{8}{2} \\\\x1=4\\\\\\x2=\frac{5-3}{2} \\\\x2=\frac{2}{2} \\\\x2=1$

Portanto, as raízes da função são 4 e 1.