Resolver a inequação letra A
Anexos:
Soluções para a tarefa
Respondido por
1
Boa tarde!
Solução!
![\dfrac{2x+1}{x+2}\ \textgreater \ 0\\\\\\
Condic\~ao!\\\\\\
x+2 \neq 0\\\\\\\\
x \neq -2\\\\\\\
2x+1\ \textgreater \ 0\\\\\\
2x\ \textgreater \ -1\\\\\
\boxed{x\ \textgreater \ - \dfrac{1}{2}}\\\\\\\
x+2\ \textless \ 0\\\\\\
\boxed{x\ \textless \ -2}\\\\\\\\
-----\circ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\circ -------\\
~~~~~~~~~~~~-2~~~~~~~~~~~~~~~~~~~~~~~~~~~ -\frac{1}{2}](https://tex.z-dn.net/?f=+%5Cdfrac%7B2x%2B1%7D%7Bx%2B2%7D%5C+%5Ctextgreater+%5C+0%5C%5C%5C%5C%5C%5C%0ACondic%5C%7Eao%21%5C%5C%5C%5C%5C%5C%0Ax%2B2+%5Cneq+0%5C%5C%5C%5C%5C%5C%5C%5C%0Ax+%5Cneq+-2%5C%5C%5C%5C%5C%5C%5C%0A2x%2B1%5C+%5Ctextgreater+%5C+0%5C%5C%5C%5C%5C%5C%0A2x%5C+%5Ctextgreater+%5C+-1%5C%5C%5C%5C%5C%0A%5Cboxed%7Bx%5C+%5Ctextgreater+%5C+-+%5Cdfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5C%5C%5C%5C%0Ax%2B2%5C+%5Ctextless+%5C+0%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Bx%5C+%5Ctextless+%5C+-2%7D%5C%5C%5C%5C%5C%5C%5C%5C%0A-----%5Ccirc%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%5Ccirc+-------%5C%5C%0A%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E-2%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E+-%5Cfrac%7B1%7D%7B2%7D+++ "\dfrac{2x+1}{x+2}\ \textgreater \ 0\\\\\\
Condic\~ao!\\\\\\
x+2 \neq 0\\\\\\\\
x \neq -2\\\\\\\
2x+1\ \textgreater \ 0\\\\\\
2x\ \textgreater \ -1\\\\\
\boxed{x\ \textgreater \ - \dfrac{1}{2}}\\\\\\\
x+2\ \textless \ 0\\\\\\
\boxed{x\ \textless \ -2}\\\\\\\\
-----\circ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\circ -------\\
~~~~~~~~~~~~-2~~~~~~~~~~~~~~~~~~~~~~~~~~~ -\frac{1}{2}")
![\boxed{Resposta:~~]- \infty~~ -2] ~~[- \frac{1}{2}~~+\infty[ }}](https://tex.z-dn.net/?f=%5Cboxed%7BResposta%3A%7E%7E%5D-++%5Cinfty%7E%7E+-2%5D+%7E%7E%5B-+%5Cfrac%7B1%7D%7B2%7D%7E%7E%2B%5Cinfty%5B+%7D%7D "\boxed{Resposta:~~]- \infty~~ -2] ~~[- \frac{1}{2}~~+\infty[ }}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
NataMachado:
Obrigado, mas está bugado
Consegui agora! Obrigado
Respondido por
1
(2x + 1)/(x + 2) é maior que 0
2x + 1 é maior que x + 2
2x - x é maior que 2 - 1
x é maior que 1
2x + 1 é maior que x + 2
2x - x é maior que 2 - 1
x é maior que 1
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