Question

Resolve pra min!! esta expressão?

Answer 1

a)

$tg(\frac{4\pi}{3})=tg(240^o)=\frac{sen(240}{cos(240^o)}=\frac{-\frac{\sqrt3}{2}}{-\frac{1}{2}}=\sqrt3$

b)

$\frac{sen180^o+cos180^o-sen270^o}{sen90^o+cos360^o}=\frac{0+(-1)-(-1)}{1+1}=\frac{0}{2}=0$