Question

resolva as equações do 2 grau incompletas​

Answer 1

Resposta:

Explicação passo-a-passo:

I)

-X²=225 (-1)

X²=-225

X=√-225

$\mathsf{\boxed{\boxed{ Esta\: func\~ao \:não \:possui \:ra\'izes \:Reais}}}$

X=+-15i

J)

-4x²+5=-59

-4x²=-64

X²=16

X=+/-√16

X=+/-4

K)

3x²+30=0

3x²=-30

X²=-10

X=+/-√-10

$\mathsf{\boxed{\boxed{ Esta \:func\~ao \:não\: possui\: ra\'izes\: Reais}}}$

X=+/-√10i

L)

X²=49

X=√49

X=+/-7

M)

4x²=36

X²=9

X=+/-√9

X=+/-3

Answer 2

Oie, Td Bom?!

i)

$- x {}^{2} = 225$

$x {}^{2} = - 225$

$x∉\mathbb{R}$

j)

$- 4x {}^{2} + 5 = - 59$

$- 4x {}^{2} = - 59 - 5$

$- 4x {}^{2} = - 64$

$x {}^{2} = 16$

$x = ± \sqrt{16}$

$x = ±4$

$x = - 4 \\ x = 4$

S = $\left \{x_{1} = - 4 \: , \: x_{2} = 4 \right \}$

k)

$3x {}^{2} + 30 = 0$

$x∉\mathbb{R}$

l)

$- 49 + x {}^{2} = 0$

$x {}^{2} = 49$

$x = ± \sqrt{49}$

$x = ±7$

$x = - 7 \\ x = 7$

S = $\left \{ x_{1} = - 7 \: , \: x_{2} = 7 \right \}$

m)

$36 = 4x {}^{2}$

$9 = x {}^{2}$

$x {}^{2} = 9$

$x = ± \sqrt{9}$

$x = ±3$

$x = - 3 \\ x = 3$

S = $\left \{ x_{1} = - 3 \: , \: x_{2} = 3 \right \}$

Att. Makaveli1996