Question

qual a altura máxima atingida pela bola nesse chute ?

Answer 1

$h(t)=-\dfrac{t^2}{2}+4t$

A altura máxima é $y_V$

$y_V=\dfrac{-\Delta}{4a}$

$\Delta=4^2-4\cdot\left(-\dfrac{1}{2}\right)\cdot0$
$\Delta=16-0$
$\Delta=16$

$y_V=\dfrac{-16}{4\cdot\left(-\dfrac{1}{2}\right)}$

$y_V=\dfrac{-16}{\dfrac{-4}{2}}$

$y_V=\dfrac{-16}{-2}$

$y_V=8$

$\boxed{\text{Resposta}:~8~\text{metros}}$