Question

Numero Complexos:

 1- Efetue

a) (4+i)+(3+3i)

b) ( 11- i^2) - (5+2i^2)

c) (5+2i)2 * (1+i)

Answer 1

a) (4+i)+(3+3i)
  4 + 3 + i + 3i = 7  + 4i

b) ( 11- i^2) - (5+2i^2)
     11 - (-1) -( 25 + 20i + 4i^2)
     11 + 1 - 25 - 20i + 4.1
             - 9 - 20i 

c) (5+2i)2 * (1+i)

    (25 + 20i + 4i^2)x(1+i)
    (25 + 20i - 4)x(1+i)
    ( 21 + 20i )(1+i)
     21 +21i +20i + 20i^2
     21 - 20 + 41i
          1 + 41i

 

Answer 2

NÚMEROS COMPLEXOS
Operações com números Complexos

$a)(4+i)+(3+3i)=7+4i$


$b)(11-i ^{2})-(5+2i ^{2})=11- i^{2}-5-2i ^{2}=6-3i ^{2}$


$c)(5+2i) ^{2}(1+i)=(5+2i)(5+2i)(1+i)=25+10i+10i+4i ^{2}(1+i)$

$25+20i+4i ^{2}(1+i)=25+20i+4(-1)(1+i)$

$25-4+20i(1+i)=(21+20i)(1+i)=21+21i+20i+20i ^{2}$

$21+41i+20(-1)=21+41i-20=1+41i$