Question

log 2 = 0,301 e log 3 = 0, 477, qual o valor de log 1,8?

Answer 1

$log 1,8=log \frac{18}{10} =log18-log10=log(2. 3^{2} )-1=log2+log 3^{2} -1=$

$log2+2log 3 -1=0,301+2.(0,477) -1=0,301+0,954-1=0,255$