Question

Resolva essa equação exponencial (1/3)^x+1=√3/9

Answer 1

$\frac{1 ^{x+1} }{3} = \frac{ \sqrt{3} }{9}$

$3^{-x-1} = \frac{ 3^{ \frac{1}{2} } }{ 3^{2} }$

$3^{-x-1} = 3^{ \frac{1}{2} - 2 }$

$-x-1 = \frac{1}{2} - 2$

$-x-1 = \frac{-3}{2}$

$-x = \frac{-3}{2} + 1$

$-x = \frac{-1}{2} .(-1)$

$x = \frac{1}{2}$