Question

Interpolar 5 meios geometricos entre 3 e 2187.

Answer 1

An=a1.q^n-1
2187=3.q^7-1
2187=3.q^6
2187=3q^6
3q^6=2187
q^6=2187/3
q^6=729
q=6^√729
q=3 #
P.G
(3,9,27,81,243,729,2187)

Answer 2

$P.G(3,?,?,?,?,?,2187)$

$Dados: \\ a_1 = 3 \\ a_n = 2187 \\ n = 7 \\ q = ?$

$a_n = a_1 *q^{n-1}$

$2187 = 3*q^{n-1}$

$q^{7-1} = 729$

$q^6 = 729$

$\boxed{q = 3}$

$\boxed{\boxed{P.G \to (3,9,27,81,243,729,2187)}}$

Espero ter ajudado. :))