Question

Gente, quanto é [(2/3)^-3 x 1/3^-4 - (1/6 - 2/1^-3)]^8

Answer 1

$({ (\frac{2}{3} )}^{ - 3} \times \frac{1}{ {3}^{ - 4} } - \frac{1}{6} - \frac{2}{ {1}^{ - 3} } ) \times 8$
${( \frac{2}{3} )}^{ - 3} = {( \frac{3}{2}) }^{3} = \frac{27}{8}$
$\frac{1}{ {3}^{ - 4} } = {3}^{4} = 81$
$\frac{2}{ {1}^{ - 3} } = 2$
$(\frac{27}{8} \times 81 - \frac{1}{6} - 2) \times 8 = \\ (\frac{27 \times 81}{8} - \frac{1}{6} - 2) \times 8 = \\ ( \frac{2187}{8} - \frac{1}{6} - 2) \times 8 = \\ \frac{13122 - 8 - 96}{48} \times 8 = \\ \frac{13018}{6} = \frac{6509}{3}$