Question

formula de bhaskara
-X²+6X-5=0

Answer 1

-x^2+6x-5=0
delta=b^2-4ac
delta=6^2-4.(-1).(-5)
delta=36-20
delta=16
x=-b-/+ raiz de delta/2a
x=-6-4/2.(-1)
x=-10/-2
x=5
x=-6+4/2.(-1)
x=-2/-2
x=1

Answer 2

- x² + 6x - 5 = 0

a = -1
b = 6
c = -5 

Delta:
Δ = b² - 4ac
Δ = 6² - 4 * (-1) * (-5)
Δ = 36 - 20
Δ = 16
        Bhaskara:
        x = - b ± √Δ / 2a
        x = - 6 ± √16 / 2 * (-1)
        x = - 6 ± 4 / -2
        x' = - 6 + 4 / -2 = -2 / -2 = 1
        x'' = - 6 - 4 / -2 = -10 / -2 = 5

S = {1, 5}

Espero ter ajudado. Valeu!