Question

f’(x)=(2x-1) (3+2x) +2(x^2-x)

Answer 1

f(x)= (2x-1).(3+2x)+2(x^2 -x)
0= (2x-1) . ( 3+2x) +2 (x^2-x)
x1= -1-√19/6
x2= -1+ √19/6