Question

Calcule os logartimos:
2)log 16 base 1/2
3)log 9/64 base 3/8

Answer 1

2 ) Log 16 base 1 / 2 = x

16 = ( 1 / 2 ) x

2⁴ = 2⁻¹ˣ

4 = - 1 x

x = - 4

3 ) Log 9 / 64 base 3 / 8 = x

9 / 64 = ( 3 / 8 )ˣ

( 3 / 8 )² = ( 3 / 8 )ˣ

x = 2

Answer 2

Boa noite Braga

2) 

log1/2(16) = -log(16)/log(2) = -log(2^4)/log(2) = -4log(2)/log(2) = -4 

3)

log3/8(9/64) = log3/8( (3/8)²) = 2log3/8(3/8) = 2

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