Question

B) y=-2×+5, sendo ×= -1,0,1,2

Answer 1

Explicação passo-a-passo:

$y( -1) = ({ - 2})^{ - 1} + 5 \\ y( - 1) = - \frac{1}{2} + 5 = \frac{9}{2} \\ \\ \\ y(0) (- {2})^{0} + 5 \\ y(0) = 1 + 5 \\ y(0) = 6 \\ \\ \\ y(1) = (- {2})^{1} + 5 \\ y(1) = - 2 + 5 \\ y(1) = 3 \\ \\ \\ y(2) = {( - 2)}^{2} + 5 \\ y(2) = 4 + 5 \\ y(2) = 9$