Question

alguem me ajuda por favor 8x-12>+10

Answer 1

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$8x-12\ \textgreater \ 10 \\ \\ 8x\ \textgreater \ 10+12 \\ \\ 8x\ \textgreater \ 22 \\ \\ x\ \textgreater \ \frac{22}{8} \\ \\ simplificando \\ \\ x\ \textgreater \ \frac{11}{4} \\ \\ S=\{x\in R /x\ \textgreater \ \frac{11}{4}\}$