Question

(2³ . 32) : 16² - ( 3⁶ : 9³)ˉ¹ =

Answer 1

$\frac{2^3.32}{16^2} - (\frac{3^6}{9^3} )^-^1$

32 = 2⁵
16² = 2⁸

$\frac{2^3.2^5}{2^8} - (\frac{3^6}{9^3} )^-^1$

9³ = 3⁶

2³ . 2⁵ = 2⁸

$\frac{2^8}{2^8} - (\frac{3^6}{3^6} )^-^1$

$1- (1)^-^1 =$

$1 -1 = 0$

Answer 2

$\frac{ 2^{3} 2^{5} }{ 2^{8} } - \frac{ 3^{6} }{ 3^{6} }$
Cortando-se as bases ficará:
5+3-8=0

OU

256/256 - 729/729=
1-1=0