Question

Y²-18y+72=0 resolva utilizando a fórmula de Bhaskara

Answer 1

D=b²-4ac                                         a=1  b=-18 c=72
D=(-18)²-4.1.72
D=324-288
D=36
X=-b+-Raiz de Delta/2.a
X=-(-18)+-Raiz de 36/2.1
X=18+-6/2
X'18+6/2
X'24/2
X'12
X''=18-6/2
X''=12/2
X''=6

Answer 2

Olá!

${y}^{2} - 18y + 72 = 0$

Onde:

a = 1
b = - 18
c = 72

Bhaskara:

/\ = (-18)² - 4 . 1 . 72
/\ = 324 - 288
/\ = 36

x' = - (-18) + 6 /2
x' = 18 + 6 /2
x' = 24 /2
x' = 12

x" = - (-18) - 6 /2
x" = 18 - 6 /2
x" = 12 /2
x" = 6

S = { 12, 6 }