Question

x²+8x-48=0,me ajudem a fazer​

Answer 1

Resposta:

x²+8x-48=0

∆= (8)² -4.1.-48 = 64 + 192 = 256

$x = \frac{ - 8 - 16}{2 \times 1} = \frac{ - 24}{2} = - 12 \\ x = \frac{ - 8 + 16}{2 \times 1} = \frac{8}{2} = 4$

x' = -12

x" = 4