Question

x² - 5x + 6 = 0 .Resolva a equação *



(R: 2, 3)

(R: 4, 3)

(R: 2, 4

(R: 3, 3)

ajuda ​

Answer 1

x² - 5x + 6 = 0

a = 1

b = -5

c = 6

Δ = b² - 4ac

Δ = (-5)² - 4 * 1 * 6

Δ = 25 - 24

Δ = 1

x = - b ± √Δ / 2a

x = - (-5) ± √1 / 2 * 1

x = 5 ± 1 / 2

x' = 5 + 1 / 2 = 6 / 2 = 3

x'' = 5 - 1 / 2 = 4 / 2 = 2

S = {2, 3}. Espero ter ajudado!❤

Answer 2

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-5x+6=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-5~e~c=6\\\\\Delta=(b)^{2}-4(a)(c)=(-5)^{2}-4(1)(6)=25-(24)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-5)-\sqrt{1}}{2(1)}=\frac{5-1}{2}=\frac{4}{2}=2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-5)+\sqrt{1}}{2(1)}=\frac{5+1}{2}=\frac{6}{2}=3\\\\S=\{2,~3\}$