Question

{x-y=11
{0,5-0,2y=4
Ajudem

Answer 1

$\left\{ \begin{array}{ccc}x&-y&=11\\0,5x&-0,2y&=4\end{array} \right \\\\\\ x - y = 11 \\\\ \boxed{\boxed{x = 11 + y}} \\\\\\ 0,5x - 0,2y = 4 \\\\ 0,5(11+y) - 0,2y = 4 \\\\ 5,5 + 0,5y - 0,2y = 4 \\\\ 0,3y = 4 - 5,5 \\\\ 0,3y = -1,5 \\\\ 3y = -15 \\\\ \boxed{\boxed{y = -5}} \\\\\\ x = 11 + y \\\\ x = 11 - 5 \\\\ \boxed{\boxed{x = 6}} \\\\\\\\ \boxed{\boxed{Resultado \rightarrow x = 6; y= -5}}$

Answer 2

X - y= 11
0,5x - 0,2y = 4 (-5)

X-y=11
-2,5x +y = -20

-1,5 x = -9 (-1)
1,5x= 9 . (10)
15x= 90
x= 90/15
x= 6

x-y=11
x-11= y
6-11= y
-5 = y
y = - 5

R.: x = 6; y = - 5