Question

x ao quadrado -8x+12=0 resolva aplicando a formula de baskara

Answer 1

x² - 8x + 12 = 0


delta = b² - 4.a.c

a = 1
b = -8
c = 12


delta = (-8)² - 4.1.12
delta = 64 - 48
delta = 16


x = -b ± √delta/2.a


x = -(-8) ± √16/2.1

x = 8 ± 4/2

x = 8 - 4/2 = 4/2 = 2

x = 8 + 4/2 = 12/2 = 6


s={ 2, 6 }




☆Espero ter ajudado!

Answer 2

$Boa tarde!! \\ \\ x^2-8x+12=0 \\\\ a=1 b=-8 c=12 \\\\ \Delta=b^2-4.a.c \\\\ \Delta=(-8)^2-4.1.12 \\\\ \Delta=64-48\\\\\Delta=16 \\ \\ Agora vamos para as duas raizes pela formula do bhaskara \\ \\ x = \dfrac{-b\pm\sqrt{\Delta}}{2a} \\ \\ x=\dfrac{-(-8)\pm\sqrt{16}}{2.1}\\ \\ x'=\dfrac{8+4}{2} \\ \\ x'=\dfrac{12}{2}=6 \\ \\ x''=\dfrac{8-4}{2}\\ \\ x''=\dfrac{4}{2}=2$