Question

X^2-6x+10=0 ajudaaa

Answer 1

Dada a equação:

$\mathsf{x^2-6x+10=0}$

Onde:

$\boxed{\mathsf{a=1;\:b=-6;\:c=10}}$

Logo:

$\mathsf{x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}\\\\\\\mathsf{x=\dfrac{-\left(-6\right)\pm \sqrt{6^2-\left(4\cdot 1\cdot 10\right)}}{2\cdot 1}}\\\\\\\mathsf{x=\dfrac{6\pm \sqrt{36-40}}{2}}\\\\\\\mathsf{x=\dfrac{6\pm \sqrt{-4}}{2}}\\\\\\\mathsf{x=\dfrac{6\pm \sqrt{4\cdot \left(-1\right)}}{2}}\\\\\\\mathsf{x=\dfrac{6\pm \left(\sqrt{4}\cdot \sqrt{-1}\right)}{2}}\\\\\\\mathsf{x=\dfrac{6\pm 2i}{2}}\\\\\\\mathsf{x=3\pm i}$

= = = = =

A equação terá duas soluções:

$\mathsf{x=3+i}\\\\\mathsf{\:\:\:\:\:ou}\\\\\mathsf{x=3-i}$

= = = = =

$\boxed{\mathsf{S=\left\{x\in \mathbb{I}\:,\:x=3+i\:\:\:\:ou\:\:\:\:x=3-i\right\}}}\: \: \checkmark$