Question

Usando as razões trigonométricas no triangulo retangulo, calcule x e y:

Answer 1

a)
$\cos(30 ) = \frac{ \sqrt{3} }{2}$
cos30° = y / 12
√3 / 2 = y / 12
2y = 12√3
y = 12√3 / 2
y = 6√3


b)
$\sin(30) = \frac{1}{2}$
sin30° = x / 10
1 / 2 = x / 10
2x = 10
x = 10 / 2
x = 5
$\sin(60) = \frac{ \sqrt{3} }{2}$
sin60° = x / y
√3 / 2 = 5 / y
√3y = 10
y = 10 / √3
y = 10 / √3 .√3 / √3
y = 10√3 / 3
solução :
$\frac{10 \sqrt{3} }{3}$