Question

usando a formula de bhaskara

g: f(x)= -x²+6x-9
h: y= x²-2x-8

Answer 1

g: f(x)=-x^2+6x-9
-x^2+6x-9=0
delta=b^2-4.a.c
delta=6^2-4.(-1).(-9)
delta=36-36
delta=0
x=-b-/+ raiz de delta/2a
x=-6-0/2. (-1)
x=-6/-2
x=3
h: y= x^2-2x-8
x^2-2x-8=0
delta=b^2-4.a.c
delta=(-2)^2-4.1. (-8)
delta=4+32
delta=36
x=-b-/+ raiz de delta/2a
x=-(-2)-6/2.1
x=2-6/2
x=-4/2
x=-2
x=-(-2)+6/2.1
x=2+6/2
x=8/2
x=4