Question

Urgente (40 pontos) Determine os valores de m para que exista x em cada caso:


A) tgx=m-1/m-2


B) tgx= raiz quadrada de m/m+1

Answer 1

$a)~tgx = \frac{m-1}{m-2}\\\\m-2 \neq 0\\m \neq 2 ~~ \\\\\textsf{Logo,~m~igual~a~qualquer~valor~diferente~de~2}$

$b)~tgx = \sqrt{\frac{{m} }{m+1}} = \frac{\sqrt{m}}{\sqrt{m+1}}\\\\m \geq 0\\\\m + 1 \neq 0 \\m \neq -1\\\\m+1 > 0\\m > -1 \\\\\textsf{Logo,~~\boxed{m\geq0}}$