Question

uma pg em que a1 = 1\4 e q= 2 qual a posicao que ocupa o termo 32

Answer 1

An = a1 + (n-1)r
A32= 1/4 + (31.2)
A32= 1/4 + 62
A32= 1 + 248
A32= 249

Answer 2

$a_n=a_1\cdot q^{n-1}$

$a_1=\dfrac{1}{4}$, $q=2$, $a_n=32$:

$32=\dfrac{1}{4}\cdot2^{n-1}$

$2^5=2^{-2}\cdot2^{n-1}$

$2^{n-1}=\dfrac{2^{5}}{2^{-2}}$

$2^{n-1}=2^{7}$

$n-1=7$

$n=8$

(1/4,1/2,1,2,4,8,16,32)