Question

$x {}^{2} - 14x + 48 = 0$
quanto é?​

Answer 1

$x^2-14x+48=0 \rightarrow \boxed{a = 1, b = -14, c = 48} \Downarrow \\\\ \Delta = b^2-4*a*c \\ \Delta = (-14)^2-4*1*(48) \\ \Delta = 196-192 \\ \Delta = 4 \\\\ x = \frac{-b\pm \sqrt{\Delta}}{2a} \\ x = \frac{14\pm2}{2} \\ \boxed{x' = \frac{14+2}{2} = \frac{16}{2} = \boxed{8}} \\ \boxed{x'' = \frac{14-2}{2} = \frac{12}{2} = \boxed{6}}$