Question

[tex]4x^{2} +9(2/3x+2) ^{2} =36

Answer 1

$4x^2 + 9 * ( \dfrac{2}{3}x + 2)^2 = 36 \\ \\ \\ 4x^2 + 9 * ( \dfrac{2x}{3} + 2)^2 = 36 \\ \\ \\ 4x^2 + 9 * ( \dfrac{2x+6}{3})^2 = 36 \\ \\ \\ 4x^2 + 9 * ( \dfrac{4x^2 + 24x + 36}{9}) = 36 \\ \\ \\ 4x^2 + 4x^2 + 24x + 36 = 36 \\ \\ 8x^2 + 24x + 36 = 36 \\ \\ 8x^2 + 24x + 36 - 36 \\ \\ \\=> 8x^2 + 24x$