Question

sendo P(x)= x² -2x+1, calcule: P(i); P(1+i); P(2-i).

Answer 1

P(x)= x² -2x+1P(i) = (i)² -2(i)+1==> -1 -2i + 1 ==> - 2i
P(1+i) =  (i+1)² -2(i+1)+1(i)²+2.(i).1+(1)² -2i-2+1 -1+2i+1-2i-2+1 ==> - 1
P(2-i)=(2-i)² -2(2-i)+1(2)²+2.2.(-i)+(-i)²-4+2i+14-4i-1- 4 + 2i+1==> - 2i