Question

sendo f (x)=3× e g (x)=[1/4]× determine:

Answer 1

a) $f(0) = 3 * 0 = 0$
b) $f(1) = 3 * 1 = 3$
c) $f(-4) = 3 * (-4) = -12$
d) $f( \frac{1}{3}) = 3 * \frac{1}{3} = 1$
e) $g(1) = (\frac{1}{4})^{1} = \frac{1}{4}$
f) $g(2) = ( \frac{1}{4})^{2} = \frac{1^{2}}{4^{2}} = \frac{1}{16}$
g) $g(-3) = ( \frac{1}{4})^{-3} = (\frac{4}{1})^{3} = 4^{3} = 64$
h) $g( \frac{1}{2} ) = (\frac{1}{4})^{ \frac{1}{2}} = \sqrt{ \frac{1}{4}} = \frac{1}{2}$