Question

sendo a +
$\sqrt{2 } = 3 \sqrt{2}$
e
$\sqrt{3b} = 5 \sqrt{6}$
determine
A - B

b/a

​

Answer 1

Resposta:

$a = 2\sqrt{2} \\b = 50$

Explicação passo-a-passo:

Calculando a:

$a + \sqrt{2}  = 3\sqrt{2} \\a = 3\sqrt{2} - \sqrt{2} \\a = \sqrt{2}* (3-1)\\a= 2\sqrt{2}$

Calculando b:

$\sqrt{3b} = 5 \sqrt{6}\\(\sqrt{3b})^2 = (5 \sqrt{6})^2\\3b = 25*6\\b = \frac{25*6}{3} \\b= 50$

Logo temos que:

$a - b = 2\sqrt{2} - 50 = -47,48\\b/a = \frac{50}{2\sqrt{2} } => \frac{25\sqrt{2} }{2} = 17,68$