Question

Sendo A=( AIJ ) 3X3 tal que AIJ =2I-J e B=( BIJ ) 1x3 tal que B e J=i+j+1,calcule A+B

Answer 1

$\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\\b31&b32&b33\end{array}\right]$   tal que aij=2i-j

b11 = 2.1-1 = 2-1=1
b12 = 2.1-2 = 2-2=0
b13 = 2.1-3 = 2-3=-1
b21 = 2.2-1 = 4-1 = 3
b22 = 2.2-2 = 4-2 = 2
b23 = 2.2-3 = 4-3 = 1
b31 = 2.3-1 = 6-1 = 5
b32 = 2.3-2 = 6-2 = 4
b33 = 2.3-3 = 6-3 = 3

$\left[\begin{array}{ccc}1&0&-1\\3&2&1\\5&4&3\end{array}\right]$


$\left[\begin{array}{ccc}b11&b12&b13\end{array}\right]$   tal que bij=i+j+1

b11 = 1+1+1 = 3
b12 = 1+2+1 = 4
b13 = 1+3+1 = 5

$\left[\begin{array}{ccc}3&4&5\end{array}\right]$

A+B = 

$\left[\begin{array}{ccc}1&0&-1\\3&2&1\\5&4&3\end{array}\right] + \left[\begin{array}{ccc}3&4&5\end{array}\right] = \left[\begin{array}{ccc}4&4&2\\3&2&1\\5&4&3\end{array}\right]$