Question

Sendo (2,5) o ponto de maximo da função f(x)=(k+3)x²-kx+1, calcule k .

Answer 1

xv=-b/2.a
yv=-Δ/4.a

Xv=-(-k)/2.(k+3)
2=k/(2k+6)
2.(2k+6)=k
4k+12=k
4k-k=-12
3k=-12
k=-12/3
k=-4