Question

Seja z=-3+8i,w=-8-3i,x=1+4i e y = -1-i,calcule:(a)z+w (b)w-y(c)w.x (d)z+x.y (e)z.w-x

Answer 1

z = -3+8i
w = -8-3i
x = 1+4i
y = -1-i

(a) z+w

$(-3+8i)+(-8-3i)\\ -3+8i-8-3i\\ -3-8+8i-3i\\ \boxed{\boxed{-11+5i}}$

(b)w-y

$(-8-3i) - (-1-i)\\ -8-3i +1+i\\ -8+1-3i+i\\ \boxed{\boxed{-7-2i}}$

(c)w.x

$(-8-3i).(1+4i)\\ -8-32i-3i-12i^{2}\\ -8-35i-12.(-1)\\ -8-35i+12\\ \boxed{\boxed{4-35i}}$

(d)z+x.y

$(-3+8i)+(1+4i).(-1-i)\\ (-3+8i)+(-1-i-4i-4i^{2})\\ (-3+8i)+(-1-5i-4.(-1))\\ (-3+8i)+(-1-5i+4)\\ (-3+8i)+(3-5i)\\ -3+8i+3-5i\\ \boxed{\boxed{3i}}$

(e)z.w-x

$(-3+8i).(-8-3i)-(1+4i)\\ (24+9i-64i-24i^{2})-(1+4i)\\ (24-55i-24.(-1))-1-4i\\ (24-55i+24)-1-4i\\ (48-55i)-1-4i\\ 48-55i-1-4i\\ \boxed{\boxed{47-59i}}$