Question

Se y = x² -5x + 6 = 0, então os zeros da função, valem

Answer 1

Explicação passo-a-passo:

$\sf x^2-5x+6=0$

$\sf \Delta=(-5)^2-4\cdot1\cdot6$

$\sf \Delta=25-24$

$\sf \Delta=1$

$\sf x=\dfrac{-(-5)\pm\sqrt{1}}{2\cdot1}=\dfrac{5\pm1}{2}$

$\sf x'=\dfrac{5+1}{2}~\Rightarrow~x'=\dfrac{6}{2}~\Rightarrow~\red{x'=3}$

$\sf x"=\dfrac{5-1}{2}~\Rightarrow~x"=\dfrac{4}{2}~\Rightarrow~\red{x'=2}$

-> 2 e 3