Question

se log.... encontra x.
a)3
b)4
c)6
d)7
$log(3x + 23) - log(2x - 3) = log4$
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Answer 1

$log(3x + 23) - log(2x - 3) = log4 \\ log( \frac{3x + 23}{2x - 3} ) - log(4) = 0\\ log( \frac{3x + 23}{8x - 12} ) = 0 \\ \\ {10}^{0} = \frac{3 x + 23 }{8x - 12} \\ 8x - 12 = 3x + 23 \\ 5x = 35 \\ x = 7$

alternativa D