Question

Sabendo que f(0) = 8 e f(2) = 12, quanto vale f(10)?

Answer 1

(0,8) e (2,12)

y=ax+b

2a+b=12
     b=8
substituir b
2a+8=12
2a=12-8
2a=4
a=4/2
a=2

y=2x+8

f(10)=2(10)+8
f(10)=20+8
f(10)=28