Question

respondam pfv gente...

Answer 1

$\dfrac{x-2}{3}+\dfrac{y}{2}=\dfrac{1}{2}$

$\dfrac{2(x-2)+3y}{6}=\dfrac{3}{6}$

$2x-4+3y=3$

$\boxed{2x+3y=7}$

$x-\dfrac{y-1}{2}=2$

$2x-y+1=4$

$\boxed{2x-y=3}$


$\begin{cases} 2x+3y=7 \\ 2x-y=3\end{cases}~\Rightarrow~\begin{cases}\ 2x+3y=7 \\ -2x+y=-3\end{cases}$

Somando membro a membro:

$4y=4$

$\boxed{y=1}$

$2x-y=3$

$2x-1=3$

$2x=4$

$\boxed{x=2}$

$\dfrac{y}{x}=\dfrac{1}{2}=0,5$

Letra A

Answer 2

a) Multiplique todos os termos por 6:

$\frac{x-2}{3}+\frac{y}{2}=\frac{1}{2}\\ \\ 2x-4+3y=3\\ \\ \boxed{2x+3y=7}$

b) Multiplique todos os termos por 2:

$x-\frac{y-1}{2}=2\\ \\ 2x-y+1=4\\ \\ \boxed{y=2x-3}$

Substituindo:

$2x+3(2x-3)=7\\ \\ 2x+6x-9=7\\ \\ 8x=16\\ \\ \boxed{x=2}\\ \\ Logo \ se: y=2x-3\rightarrow y=2.2-3=1\\ \\ \boxed{y=1}$

Finalmente,

$\boxed{\frac{y}{x}=\frac{1}{2}}$