Matemática, perguntado por elietes708, 1 ano atrás

respondam a partir da foto

Anexos:

elietes708: e pra responder todas as questões
Usuário anônimo: 9 tbm ?
elietes708: menos as que estão respondidas
Usuário anônimo: ok
elietes708: ninguém vai responder
elietes708: e urgente
elietes708: num entendi nada

Soluções para a tarefa

Respondido por Usuário anônimo
1
10)

a) \dfrac{7}{13}+\dfrac{2}{13}=\dfrac{7+2}{13}=\dfrac{9}{13}


b) \dfrac{8}{15}-\dfrac{2}{15}=\dfrac{8-2}{15}=\dfrac{6}{15}=\dfrac{2}{5}


c) \dfrac{9}{11}+\dfrac{10}{11}=\dfrac{9+10}{11}=\dfrac{19}{11}


d) \dfrac{10}{3}-\dfrac{7}{3}=\dfrac{10-7}{3}=\dfrac{3}{3}=1


e) \dfrac{13}{10}+\dfrac{29}{10}=\dfrac{13+29}{10}=\dfrac{42}{10}=\dfrac{21}{5}


f) \dfrac{31}{6}-\dfrac{17}{6}=\dfrac{31-17}{6}=\dfrac{14}{6}=\dfrac{7}{3}


g) \dfrac{5}{4}+\dfrac{2}{4}=\dfrac{5+2}{4}=\dfrac{7}{4}


h) \dfrac{11}{6}+\dfrac{1}{6}+\dfrac{5}{6}=\dfrac{11+1+5}{6}=\dfrac{17}{6}


11)


a) \dfrac{1}{3}+\dfrac{2}{5}=\dfrac{5+6}{15}=\dfrac{11}{15}


b) \dfrac{7}{2}+\dfrac{2}{3}=\dfrac{21+4}{6}=\dfrac{25}{6}


c) 2+\dfrac{1}{4}=\dfrac{8+1}{4}=\dfrac{9}{4}


d) 3\dfrac{1}{5}+2\dfrac{3}{5}=\dfrac{16}{5}+\dfrac{13}{5}=\dfrac{16+13}{5}=\dfrac{29}{5}


e) \dfrac{5}{3}+\dfrac{4}{5}+\dfrac{7}{15}=\dfrac{25+12+7}{15}=\dfrac{44}{15}


f) 4-\dfrac{1}{7}=\dfrac{28-1}{7}=\dfrac{27}{7}


i) \dfrac{3}{2}+\dfrac{2}{3}=\dfrac{9+4}{6}=\dfrac{13}{6}


j) 2\dfrac{2}{5}+\dfrac{11}{2}+\dfrac{1}{3}=\dfrac{12}{5}+\dfrac{11}{2}+\dfrac{1}{3}=\dfrac{72+165+10}{30}=\dfrac{247}{30}


k) \dfrac{7}{12}+\dfrac{5}{18}=\dfrac{21+10}{36}=\dfrac{31]{36}


l) \dfrac{1}{6}+\dfrac{5}{4}+\dfrac{2}{3}=\dfrac{2+15+8}{12}=\dfrac{25}{12}


m) \dfrac{9}{4}+\dfrac{2}{3}+\dfrac{5}{12}=\dfrac{27+8+5}{12}=\dfrac{40}{12}=\dfrac{10}{3}


n) \dfrac{3}{2}-\dfrac{2}{3}=\dfrac{9-4}{6}=\dfrac{5}{6}


q) 2-\dfrac{7}{6}+\dfrac{3}{4}=\dfrac{24-14+9}{12}=\dfrac{19}{12}


r)\dfrac{3}{4}+\dfrac{5}{6}-\dfrac{1}{2}=\dfrac{9+10-6}{12}=\dfrac{13}{12}


s) 1\dfrac{4}{5}-1\dfrac{2}{3}+\dfrac{7}{10}=\dfrac{9}{5}-\dfrac{5}{3}+\dfrac{7}{10}=\dfrac{270-250+35}{150}=\dfrac{55}{150}=\dfrac{11}{30}


t) \dfrac{1}{2}-\dfrac{1}{3}+\dfrac{5}{6}-\dfrac{3}{4}=\dfrac{6-4+10-9}{12}=\dfrac{3}{12}=\dfrac{1}{4}


u) \dfrac{1}{2}+\dfrac{1}{3}+\dfrac{5}{6}=\dfrac{3+2+5}{6}=\dfrac{10}{6}=\dfrac{5}{3}


v) 1\dfrac{1}{2}+2-\dfrac{9}{10}=\dfrac{3}{2}+2-\dfrac{9}{10}=\dfrac{15-20+9}{10}=\dfrac{4}{10}=\dfrac{2}{5}.
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