Question

resolver,C_(n+1 ,4)=C_(n , 3) exercício de combinatória

Answer 1

C(n+1,4) = C(n,3)
(n + 1) !/(n+1 - 4)! x (4)! = n!/(n-3)!x3!
(n + 1)(n) !/(n- 3)! x (4)! = n!/(n-3)!x3!
(n + 1)/(4)! = 1/3!
n+1 = 4!/3!
n+1 = 4
n=3