Question

Me Ajudeeem Por Favoor 
(x-3)(x+2)=-4 ????? 
Alguêm Sabee !!

Answer 1

$(x-3)(x+2)=-4 \\ x^2 + 2x - 3x - 6 = -4 \\ x^2 -x-6 + 4 = 0 \\ x^2 - x-2 = 0 \\ \\ \Delta = (-1)^2 - 4.1.(-2) \\ \Delta = 1 - (-8) \\ \Delta = 9 \\ \\ x = \frac{-(-1) \pm \sqrt{9} }{2.1} \\ \\ x = \frac{1 \pm 3}{2} \\ \\ x' = \frac{1+3}{2} = 2$
$x'' = \frac{1-3}{2}= -1 \\ \\ \boxed{S = \{-1;2\}}$