Question

Resolver a equação log 3 x + log 9 x = 1

Answer 1

$log(3x)+log(9x)=1\\ \\ log(27x^2)=1\\ \\ 27x^2=10^1\\ \\ x^2=\frac{10}{27}\\ \\ x=\pm\sqrt{\frac{10}{27}}$